Based on the problem statement, you are required to write a SQL query. Here is a step-by-step solution:

1. First, you need to calculate the maximum score for each hacker for each challenge. You can do this using the `GROUP BY` clause on `hacker_id` and `challenge_id` and applying the `MAX` function on the `score` column.

2. Next, you need to calculate the total score for each hacker. You can do this by grouping the result from the first step by `hacker_id` and summing up the maximum scores.

3. Then, you need to join the result from the second step with the `Hackers` table to get the names of the hackers.

4. Finally, you need to order the result by the total score in descending order and by `hacker_id` in ascending order. You also need to exclude hackers with a total score of 0.

Here is the SQL query that follows these steps:

```sql
SELECT h.hacker_id, h.name, SUM(max_score) as total_score
FROM Hackers h
JOIN (
SELECT hacker_id, MAX(score) as max_score
FROM Submissions
GROUP BY hacker_id, challenge_id
) s ON h.hacker_id = s.hacker_id
GROUP BY h.hacker_id, h.name
HAVING total_score 0
ORDER BY total_score DESC, h.hacker_id ASC;
```

This query first calculates the maximum score for each challenge for each hacker, then sums up these scores to get the total score for each hacker. It then joins this with the `Hackers` table to get the names of the hackers. The `HAVING` clause is used to exclude hackers with a total score of 0. The result is ordered by the total score in descending order and by `hacker_id` in ascending order.

Question

Based on the problem statement, you are required to write a SQL query. Here is a step-by-step solution:

1. First, you need to calculate the maximum score for each hacker for each challenge. You can do this using the `GROUP BY` clause on `hacker_id` and `challenge_id` and applying the `MAX` function on the `score` column.

2. Next, you need to calculate the total score for each hacker. You can do this by grouping the result from the first step by `hacker_id` and summing up the maximum scores.

3. Then, you need to join the result from the second step with the `Hackers` table to get the names of the hackers.

4. Finally, you need to order the result by the total score in descending order and by `hacker_id` in ascending order. You also need to exclude hackers with a total score of 0.

Here is the SQL query that follows these steps:

```sql
SELECT h.hacker_id, h.name, SUM(max_score) as total_score
FROM Hackers h
JOIN (
    SELECT hacker_id, MAX(score) as max_score
    FROM Submissions
    GROUP BY hacker_id, challenge_id
) s ON h.hacker_id = s.hacker_id
GROUP BY h.hacker_id, h.name
HAVING total_score > 0
ORDER BY total_score DESC, h.hacker_id ASC;
```

This query first calculates the maximum score for each challenge for each hacker, then sums up these scores to get the total score for each hacker. It then joins this with the `Hackers` table to get the names of the hackers. The `HAVING` clause is used to exclude hackers with a total score of 0. The result is ordered by the total score in descending order and by `hacker_id` in ascending order.

Knowee AI · Accepted Answer

Based on the problem statement, you are required to write a SQL query. Here is a step-by-step solution:

1. First, you need to calculate the maximum score for each hacker for each challenge. You can do this using the `GROUP BY` clause on `hacker_id` and `challenge_id` and applying the `MAX` function on the `score` column.

2. Next, you need to calculate the total score for each hacker. You can do this by grouping the result from the first step by `hacker_id` and summing up the maximum scores.

3. Then, you need to join the result from the second step with the `Hackers` table to get the names of the hackers.

4. Finally, you need to order the result by the total score in descending order and by `hacker_id` in ascending order. You also need to exclude hackers with a total score of 0.

Here is the SQL query that follows these steps:

```sql
SELECT h.hacker_id, h.name, SUM(max_score) as total_score
FROM Hackers h
JOIN (
    SELECT hacker_id, MAX(score) as max_score
    FROM Submissions
    GROUP BY hacker_id, challenge_id
) s ON h.hacker_id = s.hacker_id
GROUP BY h.hacker_id, h.name
HAVING total_score > 0
ORDER BY total_score DESC, h.hacker_id ASC;
```

This query first calculates the maximum score for each challenge for each hacker, then sums up these scores to get the total score for each hacker. It then joins this with the `Hackers` table to get the names of the hackers. The `HAVING` clause is used to exclude hackers with a total score of 0. The result is ordered by the total score in descending order and by `hacker_id` in ascending order.

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