The distance between two points in a plane is given by the formula:

d = sqrt[(x2 - x1)² + (y2 - y1)²]

In this case, the coordinates of the points are N(-5, -13) and P(-5, -4).

So, x1 = -5, y1 = -13, x2 = -5, and y2 = -4.

Substituting these values into the formula, we get:

d = sqrt[(-5 - (-5))² + (-4 - (-13))²]
d = sqrt[(0)² + (9)²]
d = sqrt[0 + 81]
d = sqrt[81]
d = 9

So, the distance between points N and P is 9 units.

Question

The distance between two points in a plane is given by the formula:

d = sqrt[(x2 - x1)² + (y2 - y1)²]

In this case, the coordinates of the points are N(-5, -13) and P(-5, -4).

So, x1 = -5, y1 = -13, x2 = -5, and y2 = -4.

Substituting these values into the formula, we get:

d = sqrt[(-5 - (-5))² + (-4 - (-13))²]
d = sqrt[(0)² + (9)²]
d = sqrt[0 + 81]
d = sqrt[81]
d = 9

So, the distance between points N and P is 9 units.

Knowee AI · Accepted Answer

The distance between two points in a plane is given by the formula:

d = sqrt[(x2 - x1)² + (y2 - y1)²]

In this case, the coordinates of the points are N(-5, -13) and P(-5, -4).

So, x1 = -5, y1 = -13, x2 = -5, and y2 = -4.

Substituting these values into the formula, we get:

d = sqrt[(-5 - (-5))² + (-4 - (-13))²]
d = sqrt[(0)² + (9)²]
d = sqrt[0 + 81]
d = sqrt[81]
d = 9

So, the distance between points N and P is 9 units.

Find the distance between the pair of points. Upper N left parenthesis negative 5 comma negative 13 right parenthesis, Upper P left parenthesis negative 5 comma negative 4 right parenthesis