Random variable X may take value -1 or 1; Y may take value 1, 2 or 3. The following Table shows the joint probability of random variables X and Y.Y1 2 3X -1 0.1 0.2 0.31 0.2 0.1 0.1Table 2: Joint probability distribution of X and Y. For example, the probability of X=-1 and Y=1 is 0.1. Provide solution to all questions below.(a) Marginal probability distribution of X(b) The expected value, variance and standard deviation of X. (c) Marginal probability distribution of Y(d) The expected value, variance and standard deviation of Y. (e) Conditional probability distribution of Y given X=-1.(f) The conditional expected value, conditional variance and conditional standard deviation of Y
Question
Random variable X may take value -1 or 1; Y may take value 1, 2 or 3. The following Table shows the joint probability of random variables X and Y.Y1 2 3X -1 0.1 0.2 0.31 0.2 0.1 0.1Table 2: Joint probability distribution of X and Y. For example, the probability of X=-1 and Y=1 is 0.1. Provide solution to all questions below.(a) Marginal probability distribution of X(b) The expected value, variance and standard deviation of X. (c) Marginal probability distribution of Y(d) The expected value, variance and standard deviation of Y. (e) Conditional probability distribution of Y given X=-1.(f) The conditional expected value, conditional variance and conditional standard deviation of Y
Solution
(a) To find the marginal probability distribution of X, we need to sum the joint probabilities over all possible values of Y:
P(X=-1) = 0.1 + 0.2 + 0.3 = 0.6 P(X=1) = 0.2 + 0.1 + 0.1 = 0.4
Therefore, the marginal probability distribution of X is:
X -1 1 P(X) 0.6 0.4
(b) To find the expected value of X, we can use the formula:
E(X) = Σ(xi * P(xi))
where xi are the possible values of X and P(xi) are their corresponding probabilities:
E(X) = (-1 * 0.6) + (1 * 0.4) = -0.2
To find the variance of X, we can use the formula:
Var(X) = E(X^2) - [E(X)]^2
where E(X^2) is the expected value of X squared:
E(X^2) = Σ(xi^2 * P(xi))
E(X^2) = ((-1)^2 * 0.6) + (1^2 * 0.4) = 0.8
Var(X) = 0.8 - (-0.2)^2 = 0.64
To find the standard deviation of X, we take the square root of the variance:
SD(X) = √0.64 = 0.8
Therefore, the expected value of X is -0.2, the variance of X is 0.64, and the standard deviation of X is 0.8.
(c) To find the marginal probability distribution of Y, we need to sum the joint probabilities over all possible values of X:
P(Y=1) = 0.1 + 0.2 = 0.3 P(Y=2) = 0.2 + 0.1 = 0.3 P(Y=3) = 0.3 + 0.1 = 0.4
Therefore, the marginal probability distribution of Y is:
Y 1 2 3 P(Y) 0.3 0.3 0.4
(d) To find the expected value of Y, we can use the formula:
E(Y) = Σ(yi * P(yi))
where yi are the possible values of Y and P(yi) are their corresponding probabilities:
E(Y) = (1 * 0.3) + (2 * 0.3) + (3 * 0.4) = 2.2
To find the variance of Y, we can use the formula:
Var(Y) = E(Y^2) - [E(Y)]^2
where E(Y^2) is the expected value of Y squared:
E(Y^2) = Σ(yi^2 * P(yi))
E(Y^2) = (1^2 * 0.3) + (2^2 * 0.3) + (3^2 * 0.4) = 5
Var(Y) = 5 - 2.2^2 = 0.76
To find the standard deviation of Y, we take the square root of the variance:
SD(Y) = √0.76 ≈ 0.87
Therefore, the expected value of Y is 2.2, the variance of Y is 0.76, and the standard deviation of Y is approximately 0.87.
(e) To find the conditional probability distribution of Y given X=-1, we need to divide the joint probabilities of X=-1 and each value of Y by the marginal probability of X=-1:
P(Y=1|X=-1) = 0.1 / 0.6 = 1/6 P(Y=2|X=-1) = 0.2 / 0.6 = 1/3 P(Y=3|X=-1) = 0.3 / 0.6 = 1/2
Therefore, the conditional probability distribution of Y given X=-1 is:
Y 1/6 1/3 1/2 P(Y|X=-1) 1/10 2/10 3/10
(f) To find the conditional expected value of Y given X=-1, we can use the formula:
E(Y|X=-1) = Σ(yi * P(yi|X=-1))
where yi are the possible values of Y and P(yi|X=-1) are their corresponding conditional probabilities:
E(Y|X=-1) = (1 * 1/10) + (2 * 2/10) + (3 * 3/10) = 2
To find the conditional variance of Y given X=-1, we can use the formula:
Var(Y|X=-1) = E(Y^2|X=-1) - [E(Y|X=-1)]^2
where E(Y^2|X=-1) is the expected value of Y squared given X=-1:
E(Y^2|X=-1) = Σ(yi^2 * P(yi|X=-1))
E(Y^2|X=-1) = (1^2 * 1/10) + (2^2 * 2/10) + (3^2 * 3/10) = 2.3
Var(Y|X=-1) = 2.3 - 2^2 = 0.3
To find the conditional standard deviation of Y given X=-1, we take the square root of the conditional variance:
SD(Y|X=-1) = √0.3 ≈ 0.55
Therefore, the conditional expected value of Y given X=-1 is 2, the conditional variance of Y given X=-1 is 0.3, and the conditional standard deviation of Y given X=-1 is approximately 0.55.
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