Determine the smallest digit number which is exactly divisible by 66, 99 and 1212.

To find the smallest number that is exactly divisible by 66, 99, and 1212, we need to find the least common multiple (LCM) of these three numbers.

Step 1: Prime factorization of the numbers

• 66 = 2 * 3 * 11
• 99 = 3^2 * 11
• 1212 = 2^2 * 3 * 101

Step 2: Find the LCM The LCM is found by multiplying the highest power of all the prime numbers in the three numbers. So, LCM = 2^2 * 3^2 * 11 * 101 = 13332

Therefore, the smallest number that is exactly divisible by 66, 99, and 1212 is 13332.