In a two-tailed hypothesis test situation, the test statistic is determined to be t = -2.032. The sample size is 35. The p-value for this test is-.05.+.05.-.10.+.10.

The question seems to be asking for the p-value of a two-tailed hypothesis test where the test statistic (t) is -2.032 and the sample size is 35. However, the p-value is not something that can be calculated from just the test statistic and the sample size. The p-value is the probability of obtaining a result as extreme as the observed results of a statistical hypothesis test, assuming that the null hypothesis is correct. It is determined by the statistical significance of the test statistic in the context of the specific statistical test being performed.

In a two-tailed test, the p-value is the probability of obtaining a result as extreme as the observed test statistic in either tail of the distribution. This means that if the test statistic falls in the left tail of the distribution, the p-value is the sum of the probabilities of obtaining a result as extreme as the observed test statistic in either the left or the right tail.

To calculate the p-value, you would typically use a statistical software or a t-distribution table. The degrees of freedom for the t-distribution would be the sample size minus 1, which in this case is 35 - 1 = 34. You would look up the probability associated with the absolute value of the test statistic (2.032) in a t-distribution table with 34 degrees of freedom.

However, the question seems to be suggesting that the p-value is either -.05, +.05, -.10, or +.10. This is confusing because p-values are always positive and represent a probability, so they should be between 0 and 1. It's possible that there may be a misunderstanding or error in the question.