The reaction that proceeds by a free radical mechanism in the presence of UV light is D. CH3CH3 + Cl2 → CH3CH2Cl + HCl.

Here's a step-by-step explanation:

1. The reaction starts with the homolytic cleavage of the Cl-Cl bond in the presence of UV light, which results in the formation of two chlorine free radicals.

2. These chlorine free radicals are very reactive and can abstract a hydrogen atom from the ethane (CH3CH3) molecule, forming a new H-Cl bond and leaving behind an ethyl free radical (CH3CH2•).

3. The ethyl free radical can then react with another molecule of Cl2, forming a new C-Cl bond and another chlorine free radical.

4. This chlorine free radical can then go on to react with another ethane molecule, and the process repeats. This is known as a chain reaction.

This type of reaction is characteristic of free radical halogenation, which is a common type of reaction that proceeds via a free radical mechanism.

Question

The reaction that proceeds by a free radical mechanism in the presence of UV light is D. CH3CH3 + Cl2 → CH3CH2Cl + HCl.

Here's a step-by-step explanation:

1. The reaction starts with the homolytic cleavage of the Cl-Cl bond in the presence of UV light, which results in the formation of two chlorine free radicals.

2. These chlorine free radicals are very reactive and can abstract a hydrogen atom from the ethane (CH3CH3) molecule, forming a new H-Cl bond and leaving behind an ethyl free radical (CH3CH2•).

3. The ethyl free radical can then react with another molecule of Cl2, forming a new C-Cl bond and another chlorine free radical.

4. This chlorine free radical can then go on to react with another ethane molecule, and the process repeats. This is known as a chain reaction.

This type of reaction is characteristic of free radical halogenation, which is a common type of reaction that proceeds via a free radical mechanism.

Knowee AI · Accepted Answer

The reaction that proceeds by a free radical mechanism in the presence of UV light is D. CH3CH3 + Cl2 → CH3CH2Cl + HCl.

Here's a step-by-step explanation:

1. The reaction starts with the homolytic cleavage of the Cl-Cl bond in the presence of UV light, which results in the formation of two chlorine free radicals.

2. These chlorine free radicals are very reactive and can abstract a hydrogen atom from the ethane (CH3CH3) molecule, forming a new H-Cl bond and leaving behind an ethyl free radical (CH3CH2•).

3. The ethyl free radical can then react with another molecule of Cl2, forming a new C-Cl bond and another chlorine free radical.

4. This chlorine free radical can then go on to react with another ethane molecule, and the process repeats. This is known as a chain reaction.

This type of reaction is characteristic of free radical halogenation, which is a common type of reaction that proceeds via a free radical mechanism.

Which of these reactions proceeds by a free radical mechanism in the presence of UV light?A. C6H6 + Cl2 → C6H5Cl + HClB. C6H6 + 3H2 → C6H12C. CH2CH2 + HBr → CH3CH2BrD. CH3CH3 + Cl2 → CH3CH2Cl + HCl

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