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Factor completely 4x2 + 25x + 6.Group of answer choices(4x + 1)(x + 6)(4x + 6)(x + 1)(2x + 3)(2x + 2)(2x + 6)(2x + 1)

Question

Factor completely 4x2 + 25x + 6.Group of answer choices(4x + 1)(x + 6)(4x + 6)(x + 1)(2x + 3)(2x + 2)(2x + 6)(2x + 1)

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Solution

To factor the quadratic equation 4x^2 + 25x + 6 completely, we first need to find two numbers that multiply to (4*6)=24 and add up to 25. Those numbers are 24 and 1.

Now, we rewrite the middle term (25x) of the quadratic equation as the sum of (24x + x), and then group the terms:

4x^2 + 24x + x + 6

This gives us two groups: (4x^2 + 24x) and (x + 6).

We factor out the greatest common factor from each group:

4x(x + 6) + 1(x + 6)

Now, you can see that (x + 6) is a common factor. So, we can factor that out:

(4x + 1)(x + 6)

So, the completely factored form of the quadratic equation 4x^2 + 25x + 6 is (4x + 1)(x + 6).

This problem has been solved

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