Here is a step-by-step guide to complete the program in C: 1. First, include the necessary libraries. In this case, we need the standard input/output library. ```c #include ``` 2. Declare the main function. ```c int main() { ``` 3. Declare the necessary variables. We need a character to store the data type identifier and a void pointer to store the value. ```c char type; void *value; ``` 4. Prompt the user to enter the data type identifier and read it. ```c printf("Enter data type identifier (i for integer, f for float): "); scanf("%c", &type); ``` 5. Depending on the entered identifier, prompt the user to enter the corresponding value and store it in the void pointer. Use a switch statement for this. ```c switch(type) { case 'i': { int *intValue = malloc(sizeof(int)); printf("Enter integer value: "); scanf("%d", intValue); value = intValue; break; } case 'f': { float *floatValue = malloc(sizeof(float)); printf("Enter float value: "); scanf("%f", floatValue); value = floatValue; break; } default: { printf("Invalid type entered! "); return 0; } } ``` 6. Print the entered value with the appropriate data type label. ```c switch(type) { case 'i': { printf("Integer: %d ", *(int *)value); break; } case 'f': { printf("Float: %f ", *(float *)value); break; } } ``` 7. Free the allocated memory and return 0 to indicate that the program has finished successfully. ```c free(value); return 0; } ``` Please note that this program uses dynamic memory allocation to store the entered value. This is necessary because we don't know the size of the value at compile time.

Question

Here is a step-by-step guide to complete the program in C:

1. First, include the necessary libraries. In this case, we need the standard input/output library.

```c
#include <stdio.h>
```

2. Declare the main function.

```c
int main() {
```

3. Declare the necessary variables. We need a character to store the data type identifier and a void pointer to store the value.

```c
    char type;
    void *value;
```

4. Prompt the user to enter the data type identifier and read it.

```c
    printf("Enter data type identifier (i for integer, f for float): ");
    scanf("%c", &type);
```

5. Depending on the entered identifier, prompt the user to enter the corresponding value and store it in the void pointer. Use a switch statement for this.

```c
    switch(type) {
        case 'i': {
            int *intValue = malloc(sizeof(int));
            printf("Enter integer value: ");
            scanf("%d", intValue);
            value = intValue;
            break;
        }
        case 'f': {
            float *floatValue = malloc(sizeof(float));
            printf("Enter float value: ");
            scanf("%f", floatValue);
            value = floatValue;
            break;
        }
        default: {
            printf("Invalid type entered!
");
            return 0;
        }
    }
```

6. Print the entered value with the appropriate data type label.

```c
    switch(type) {
        case 'i': {
            printf("Integer: %d
", *(int *)value);
            break;
        }
        case 'f': {
            printf("Float: %f
", *(float *)value);
            break;
        }
    }
```

7. Free the allocated memory and return 0 to indicate that the program has finished successfully.

```c
    free(value);
    return 0;
}
```

Please note that this program uses dynamic memory allocation to store the entered value. This is necessary because we don't know the size of the value at compile time.

Knowee AI · Accepted Answer

Here is a step-by-step guide to complete the program in C:

1. First, include the necessary libraries. In this case, we need the standard input/output library.

```c
#include <stdio.h>
```

2. Declare the main function.

```c
int main() {
```

3. Declare the necessary variables. We need a character to store the data type identifier and a void pointer to store the value.

```c
    char type;
    void *value;
```

4. Prompt the user to enter the data type identifier and read it.

```c
    printf("Enter data type identifier (i for integer, f for float): ");
    scanf("%c", &type);
```

5. Depending on the entered identifier, prompt the user to enter the corresponding value and store it in the void pointer. Use a switch statement for this.

```c
    switch(type) {
        case 'i': {
            int *intValue = malloc(sizeof(int));
            printf("Enter integer value: ");
            scanf("%d", intValue);
            value = intValue;
            break;
        }
        case 'f': {
            float *floatValue = malloc(sizeof(float));
            printf("Enter float value: ");
            scanf("%f", floatValue);
            value = floatValue;
            break;
        }
        default: {
            printf("Invalid type entered!
");
            return 0;
        }
    }
```

6. Print the entered value with the appropriate data type label.

```c
    switch(type) {
        case 'i': {
            printf("Integer: %d
", *(int *)value);
            break;
        }
        case 'f': {
            printf("Float: %f
", *(float *)value);
            break;
        }
    }
```

7. Free the allocated memory and return 0 to indicate that the program has finished successfully.

```c
    free(value);
    return 0;
}
```

Please note that this program uses dynamic memory allocation to store the entered value. This is necessary because we don't know the size of the value at compile time.

Question

Solution

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