What is the pressure on a swimmer 50m below the surface of a lake: Use: ρwater= 1,000 kg/m3, Patm = 105Pa and g=10m/s2Question 4Answera.20,000Pab.600,000Pac.2,000,000Pad.2,000Pa
Question
What is the pressure on a swimmer 50m below the surface of a lake: Use: ρwater= 1,000 kg/m3, Patm = 105Pa and g=10m/s2Question 4Answera.20,000Pab.600,000Pac.2,000,000Pad.2,000Pa
Solution
The pressure experienced by a swimmer under water is the sum of the atmospheric pressure and the pressure due to the weight of the water above the swimmer.
The pressure due to the water can be calculated using the formula:
P = ρ * g * h
where: ρ is the density of the water, g is the acceleration due to gravity, and h is the depth below the surface of the water.
Given: ρ = 1,000 kg/m³, g = 10 m/s², and h = 50 m.
Substituting these values into the formula, we get:
P = 1,000 kg/m³ * 10 m/s² * 50 m = 500,000 Pa.
Adding this to the atmospheric pressure (Patm = 105,000 Pa), we get:
Total pressure = 500,000 Pa + 105,000 Pa = 605,000 Pa.
So, the pressure on the swimmer 50 m below the surface of the lake is 605,000 Pa, which is closest to option b. 600,000 Pa.
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