To solve this problem, we first need to understand that the train is currently running at 7/11 of its own speed. This means it's running slower than its normal speed.

1. Let's assume the normal speed of the train is x km/h and the distance to the place is d km.

2. When the train is running at 7/11 of its own speed, its speed is (7/11)x km/h.

3. The time it takes to reach the place is distance divided by speed, so in this case, it's d / [(7/11)x] = 22 hours.

4. From this equation, we can find that the distance d = 22 * (7/11)x = 14x km.

5. If the train runs at its own speed, the time it would take is distance divided by speed, so it's d / x = 14x / x = 14 hours.

6. The time saved if the train would run at its own speed is the original time minus the time it would take at its own speed, so it's 22 hours - 14 hours = 8 hours.

So, the correct answer is 8 hours.

Question

To solve this problem, we first need to understand that the train is currently running at 7/11 of its own speed. This means it's running slower than its normal speed.

1. Let's assume the normal speed of the train is x km/h and the distance to the place is d km.

2. When the train is running at 7/11 of its own speed, its speed is (7/11)x km/h.

3. The time it takes to reach the place is distance divided by speed, so in this case, it's d / [(7/11)x] = 22 hours.

4. From this equation, we can find that the distance d = 22 * (7/11)x = 14x km.

5. If the train runs at its own speed, the time it would take is distance divided by speed, so it's d / x = 14x / x = 14 hours.

6. The time saved if the train would run at its own speed is the original time minus the time it would take at its own speed, so it's 22 hours - 14 hours = 8 hours.

So, the correct answer is 8 hours.

Knowee AI · Accepted Answer

To solve this problem, we first need to understand that the train is currently running at 7/11 of its own speed. This means it's running slower than its normal speed.

1. Let's assume the normal speed of the train is x km/h and the distance to the place is d km.

2. When the train is running at 7/11 of its own speed, its speed is (7/11)x km/h.

3. The time it takes to reach the place is distance divided by speed, so in this case, it's d / [(7/11)x] = 22 hours.

4. From this equation, we can find that the distance d = 22 * (7/11)x = 14x km.

5. If the train runs at its own speed, the time it would take is distance divided by speed, so it's d / x = 14x / x = 14 hours.

6. The time saved if the train would run at its own speed is the original time minus the time it would take at its own speed, so it's 22 hours - 14 hours = 8 hours.

So, the correct answer is 8 hours.

Select the correct answerA train running at 711 of its own speed reached a place in 22 hours. How much time could be saved if the train would run at its own speed?Options7 hours14 hours8 hours16 hours

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