How many moles is 573.28 g of AgCl?A.5 molB.3 molC.4 molD.2 molSUBMITarrow_backPREVIOUS
Question
How many moles is 573.28 g of AgCl?A.5 molB.3 molC.4 molD.2 molSUBMITarrow_backPREVIOUS
Solution
To answer this question, we first need to know the molar mass of AgCl. The molar mass of AgCl (Silver Chloride) is approximately 143.32 g/mol.
Step 1: Identify the given mass and the molar mass of the substance. Given mass = 573.28 g Molar mass of AgCl = 143.32 g/mol
Step 2: Use the formula to calculate the number of moles. Number of moles = Given mass / Molar mass
Step 3: Substitute the given values into the formula. Number of moles = 573.28 g / 143.32 g/mol = 4 mol
So, the answer is C. 4 mol.
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