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Using the properties of determinants, show that(a)a3 a2 1b3 b2 1c3 c2 1

Question

Using the properties of determinants, show that(a)a3 a2 1b3 b2 1c3 c2 1

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Solution

The given matrix is:

| a³ a² 1 | | b³ b² 1 | | c³ c² 1 |

We can use the properties of determinants to simplify this.

Step 1: Subtract the second column from the first, and the third column from the second. This gives us:

| a³-a² a²-1 1 | | b³-b² b²-1 1 | | c³-c² c²-1 1 |

Step 2: Factor out a², b², and c² from the first and second columns:

| a²(a-1) a²(1-1/a) 1 | | b²(b-1) b²(1-1/b) 1 | | c²(c-1) c²(1-1/c) 1 |

Step 3: Now, we can see that the first two columns are proportional, so the determinant of this matrix is 0.

Therefore, the determinant of the original matrix is also 0.

This problem has been solved

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