Solve the equation for all real solutions in simplest form.d, squared, minus, 9, d, plus, 2, equals, 0d 2 −9d+2=0
Question
Solve the equation for all real solutions in simplest form.d, squared, minus, 9, d, plus, 2, equals, 0d 2 −9d+2=0
Solution
The equation you provided is a quadratic equation. The general form of a quadratic equation is ax^2 + bx + c = 0. In this case, a = 1, b = -9, and c = 2.
To solve for d, we can use the quadratic formula, which is d = [-b ± sqrt(b^2 - 4ac)] / (2a).
Substituting the values of a, b, and c into the formula, we get:
d = [9 ± sqrt((-9)^2 - 412)] / (2*1) d = [9 ± sqrt(81 - 8)] / 2 d = [9 ± sqrt(73)] / 2
So, the solutions for d are:
d = (9 + sqrt(73)) / 2 d = (9 - sqrt(73)) / 2
These are the real solutions for the equation in simplest form.
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