If secθ - tanθ =,(0<x<y) and 0°<θ<90°, then sinθ is equal to:
Question
If secθ - tanθ =,(0<x<y) and 0°<θ<90°, then sinθ is equal to:
Solution
The question seems to be incomplete. The expression "secθ - tanθ =" is not followed by any value or expression. Could you please provide the complete question?
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