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If  cos 40 sin 30x    , find the value of x

Question

If  cos 40 sin 30x    , find the value of x

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Solution

To find the value of x in the equation cos(40°) + sin(30°x) = 0, we can follow these steps:

Step 1: Subtract cos(40°) from both sides of the equation: sin(30°x) = -cos(40°)

Step 2: Take the sine of both sides of the equation: sin(sin(30°x)) = sin(-cos(40°))

Step 3: Use the identity sin(-θ) = -sin(θ): sin(30°x) = -sin(40°)

Step 4: Use the identity sin(θ) = sin(180° - θ): sin(30°x) = sin(180° - 40°)

Step 5: Simplify the right side of the equation: sin(30°x) = sin(140°)

Step 6: Set up the equation for the possible values of x: 30°x = 140° + 360°n or 30°x = 180° - 140° + 360°n

Step 7: Solve for x: x = (140° + 360°n) / 30° or x = (180° - 140° + 360°n) / 30°

So, the value of x can be expressed as (140° + 360°n) / 30° or (180° - 140° + 360°n) / 30°, where n is an integer.

This problem has been solved

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