Find ℎ(3) + 𝑎(2) if ℎ(𝑥) = 𝑥 − 1 and 𝑎(𝑥) = 7𝑥 + 3

To find ℎ(3) + 𝑎(2), we first need to substitute the values of 3 and 2 into the functions ℎ(𝑥) and 𝑎(𝑥) respectively.

Step 1: Substitute x = 3 into ℎ(𝑥) = 𝑥 − 1 ℎ(3) = 3 - 1 = 2

Step 2: Substitute x = 2 into 𝑎(𝑥) = 7𝑥 + 3 𝑎(2) = 7*2 + 3 = 14 + 3 = 17

Step 3: Add the results of ℎ(3) and 𝑎(2) ℎ(3) + 𝑎(2) = 2 + 17 = 19

So, ℎ(3) + 𝑎(2) = 19.