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The sound intensity at a person’s seat in a concert hall is 8.010–5 W m–2. Calculate thesound intensity level, in decibels, at the seat. (Use 1.010–12 W m–2 as the reference level.)

Question

The sound intensity at a person’s seat in a concert hall is 8.010–5 W m–2. Calculate thesound intensity level, in decibels, at the seat. (Use 1.010–12 W m–2 as the reference level.)

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Solution

To calculate the sound intensity level in decibels, we use the formula:

L = 10 log (I/I0)

where: L is the sound level in decibels, I is the intensity of the sound wave, and I0 is the reference intensity.

Given in the problem, I = 8.0 x 10^-5 W/m^2 and I0 = 1.0 x 10^-12 W/m^2.

Substituting these values into the formula, we get:

L = 10 log (8.0 x 10^-5 / 1.0 x 10^-12)

Solving this, we get:

L = 10 log (8.0 x 10^7)

Using the property of logarithms that log (a*b) = log(a) + log(b), we can simplify this to:

L = 10 [log (8.0) + log (10^7)]

Since log (10^7) = 7, this simplifies to:

L = 10 [log (8.0) + 7]

Finally, calculating log (8.0) approximately equals to 0.9031, we get:

L = 10 [0.9031 + 7]

L = 10 * 7.9031

L = 79.031 dB

So, the sound intensity level at the person's seat in the concert hall is approximately 79 dB.

This problem has been solved

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