Consider the following fragment of a program: ... int a=0; int main() { a = 1; int pid=fork(); if(pid == 0) { printf("%d\n", a); } else if(pid > 0) { printf("%d\n", a); } return 0; } When run, what output do you observe and what do you think is the reason for the observed output? You may assume that the call to fork() succeeds. Question 4 Select one: a. The parent process outputs 1, but the child process outputs 0, because the value of a is updated only in the parent process. b. Both the parent and the child processes output 1, because the child process inherits the memory state from the parent at the point where fork() is called, and the variable a has been assigned the value 1 at that point. c. The parent process outputs 0, but the child process outputs 1, because the value of a is updated only in the child process.

What could be an issue with the following program? Assume the child process is executed immediately after forked. int main() { int pid=fork(); if(pid < 0) exit(1); if(pid == 0) { printf("hello world\n"); } else if(pid > 0) { sleep(100000) ; } return 0; } Select one: a. It may create a zombie process. b. It may cause other processes to starve by hogging CPU time executing sleep. c. It may create an orphan process.

What all gets printed when the following program is compiled and run.public class Test{ public static void main(String args[]){ int i, j=1; i = (j>1)?2:1; switch(i){ case 0: System.out.println(0); break; case 1: System.out.println(1); case 2: System.out.println(2); break; case 3: System.out.println(3); break; } }}01212

3-2-8: Consider the following code segment.int x = 5;if (x < 5){ x = 3 * x;}if (x % 2 == 1){ x = x / 2;}System.out.print(2*x + 1);What is printed as a result of executing the code segment?A. 3B. 11C. 31D. 15E. 5

estion: What is the purpose of the "fork" system call in Unix-like operating systems?A) To create a new processB) To terminate a processC) To wait f

What will print out when the following code runs?