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A solenoid with 500 loops has a cross sectional area of 8 cm2. It is suddenly transferred from a region where the magnetic field is 0.5 T to a region where there is no magnetic field. If the transfer requires 0.04 s and the resistance of the solenoid is 4 Ω. Determine : i)                    Magnetic flux

Question

A solenoid with 500 loops has a cross sectional area of 8 cm2. It is suddenly transferred from a region where the magnetic field is 0.5 T to a region where there is no magnetic field. If the transfer requires 0.04 s and the resistance of the solenoid is 4 Ω. Determine : i)                    Magnetic flux

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Solution

To calculate the magnetic flux (Φ), we use the formula:

Φ = B * A * N

where: B = magnetic field = 0.5 T A = cross-sectional area = 8 cm² = 8 * 10^-4 m² (since 1 cm² = 10^-4 m²) N = number of loops = 500

Substituting these values into the formula, we get:

Φ = 0.5 T * 8 * 10^-4 m² * 500 Φ = 0.2 Wb (Weber)

So, the magnetic flux is 0.2 Weber.

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