Quantitative Aptitude: Ages [Section 1 of 1] Q6 of 30 Marks 1 General Instructions 100% ×CloseTest time left: 29:21Select the correct answerThe ages of two persons differ by 20 years. If 5 years ago, the elder one be 5 times as old as the younger one, their present ages (in years) are respectively?
Question
Quantitative Aptitude: Ages [Section 1 of 1] Q6 of 30 Marks 1 General Instructions 100% ×CloseTest time left: 29:21Select the correct answerThe ages of two persons differ by 20 years. If 5 years ago, the elder one be 5 times as old as the younger one, their present ages (in years) are respectively?
Solution
Let's denote the present age of the elder person as E and the present age of the younger person as Y.
From the problem, we know that:
-
E - Y = 20 (The ages of two persons differ by 20 years)
-
E - 5 = 5(Y - 5) (5 years ago, the elder one was 5 times as old as the younger one)
We can solve these two equations to find the values of E and Y.
Let's start with the second equation:
E - 5 = 5Y - 25
=> E = 5Y - 20
Now, we can substitute E from the first equation into this:
20 + Y = 5Y - 20
=> 40 = 4Y
=> Y = 10
Substituting Y = 10 into the first equation:
E = 20 + 10 = 30
So, the present ages of the elder and younger person are 30 and 10 years respectively.
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