Knowee
Questions
Features
Study Tools

Q.8 Three vectors are as follows: ๐‘Ž๐‘Žโƒ— = 3๐‘–๐‘–ฬ‚ โˆ’ 10๐‘—๐‘—ฬ‚ + 7๐‘˜๐‘˜๏ฟฝ ๐‘๐‘๏ฟฝโƒ— = โˆ’9๐‘–๐‘–ฬ‚ + 6๐‘—๐‘—ฬ‚ โˆ’ 47๐‘˜๐‘˜๏ฟฝ ๐‘๐‘โƒ— = 11๐‘–๐‘–ฬ‚ โˆ’ 17๐‘˜๐‘˜๏ฟฝ The value of ๏ฟฝ๐‘Ž๐‘Žโƒ— + ๐‘๐‘๏ฟฝโƒ— ๏ฟฝ โ‹… ๐‘๐‘โƒ— is (A) 614 (B) 746 (C) 2 (D) 134

Question

Q.8 Three vectors are as follows: ๐‘Ž๐‘Žโƒ— = 3๐‘–๐‘–ฬ‚ โˆ’ 10๐‘—๐‘—ฬ‚ + 7๐‘˜๐‘˜๏ฟฝ ๐‘๐‘๏ฟฝโƒ— = โˆ’9๐‘–๐‘–ฬ‚ + 6๐‘—๐‘—ฬ‚ โˆ’ 47๐‘˜๐‘˜๏ฟฝ ๐‘๐‘โƒ— = 11๐‘–๐‘–ฬ‚ โˆ’ 17๐‘˜๐‘˜๏ฟฝ The value of ๏ฟฝ๐‘Ž๐‘Žโƒ— + ๐‘๐‘๏ฟฝโƒ— ๏ฟฝ โ‹… ๐‘๐‘โƒ— is (A) 614 (B) 746 (C) 2 (D) 134

๐Ÿง Not the exact question you are looking for?Go ask a question

Solution

To solve this problem, we first need to add vectors ๐‘Ž๐‘Žโƒ— and ๐‘๐‘โƒ—.

The sum of the vectors ๐‘Ž๐‘Žโƒ— and ๐‘๐‘โƒ— is calculated as follows:

๐‘Ž๐‘Žโƒ— + ๐‘๐‘โƒ— = (3๐‘– - 10๐‘— + 7๐‘˜) + (-9๐‘– + 6๐‘— - 47๐‘˜) = (3 - 9)๐‘– + (-10 + 6)๐‘— + (7 - 47)๐‘˜ = -6๐‘– - 4๐‘— - 40๐‘˜

Next, we need to find the dot product of the vector sum (๐‘Ž๐‘Žโƒ— + ๐‘๐‘โƒ—) and ๐‘๐‘โƒ—.

The dot product of two vectors is calculated as follows:

(๐‘Ž๐‘Žโƒ— + ๐‘๐‘โƒ—) โ‹… ๐‘๐‘โƒ— = (-6๐‘– - 4๐‘— - 40๐‘˜) โ‹… (11๐‘– - 17๐‘˜) = -611 + -40 + -40*(-17) = -66 + 0 + 680 = 614

So, the value of (๐‘Ž๐‘Žโƒ— + ๐‘๐‘โƒ—) โ‹… ๐‘๐‘โƒ— is 614. Therefore, the correct answer is (A) 614.

This problem has been solved

Similar Questions

Determine which of the following vectors are equal:๐‘ข1=1,2,3,๐‘ข2=2,3,1,ย ๐‘ข3=1,3,2,ย ๐‘ข4=2,3,1

Let ๐ด = โˆ’2, 3 and ๐ต = 4, 5 . Express the vector ๐ด๐ต in ๐‘ฃ = ๐‘Ž๐’Š + ๐‘๐’‹ form

Let uห‰=โŸจ0,โˆ’2โŸฉ,vห‰=โŸจ4,3โŸฉ, and wห‰=โŸจ0,-4โŸฉ. Find the vector xห‰ that satisfies 5uห‰โˆ’vห‰+xห‰=2xห‰+wห‰ In this case, xห‰=

Given the following vectors, calculate โˆ’7u+4vโˆ’7๐‘ข+4๐‘ฃ.u=โŸจ2,9โŸฉ๐‘ข=โŸจ2,9โŸฉ, v=โŸจโˆ’8,0โŸฉ

Find the magnitude of vector ๐ด = 3๐‘– + 2๐‘— + ๐‘˜

1/3

Upgrade your grade with Knowee

Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.