A study found that between 2011 and 2015, about 60.1% of workers commuted less than 26 minutes to work. The margin of error for the study was 1.9%.  Find the 95% confidence interval for this situation.(Enter the smallest value in the first blank and the largest value in the last blank. Do not add % sign)( %, % )

After surveying 500 college students, a marketing company found that the average amount of time college students spend doing laundry is 2 hours per week.  The standard deviation is 0.25 hour, and confidence interval is 95%.  (Note: The critical value for a 95% confidence interval is 1.96.)  Use the formula below to find the margin of error, where s is the standard deviation and n is the sample size.  Margin of Error = 1.96(sn√)

Researchers want to estimate the mean time people spend grocery shopping per week. If they want the margin of error to be within 1.5 hour, how many people should they survey? Assume that they want to calculate a 95% confidence interval and the population standard deviation is about 5.8 hours.

The table below shows a sample of 4 commuters in Chicago showed the the commuting times in minutes. Find the following:time33.936.937.927.5At 98% confidence level, the maximum error of estimate (positive) is equal to: Find the 98% lower confidence interval of the true mean commuting times.

In a survey of 500 college students, 250 of them said they had stayed up late more than 10 times in the past year. A 95% confidence interval is constructed based on the percentage of college students in this sample who stay up late more than 10 times. What is the lower limit for the interval? (round the answer to two decimal places)

How many work cycles should be timed to estimate the average cycle time to within 1 percent of the sample mean with a confidence of 95.0 percent if a pilot study yielded these times (in minutes): 4.9, 4.1, 4.3, 4.1, 4.3, and 4.6? (Round the final answer to the nearest whole number.)