f X~ N(0, 1), Y~N(0, 4), Z~N(0, 25). X, Y, Z are pairwise independent. Then

f X~ N(0, 1), Y~N(0, 4), Z~N(0, 25). X, Y, Z are pairwise independent. Then X+Y+Z ~ N(0, 64)X+Y+Z ~ N(0, 29)X+Y+Z ~N(0, 30)X+Y+Z~ N(0,50)

f (x, y, z) = x2 y3 z4 .

Consider the Boolean function of four variables: f(w,x,y,z) = ∑(1,3,4,6,9,11,12,14) The function is: (A) Independent of one variables(B) Independent of two variables(C) Independent of three variables(D) Dependent on all the variables

Find the Conjunctive normal for and Disjunctive normal form ofgiven Boolean function f(x, y, z)=(xvy) (xvz).

Given 5.0||)5.0(4)( 2 >+= zzzzX Find the Z-Transform of the following signals.(a) y[n] = x[ n – 2] (b) e[n] = x[–n] (c) d[n] = 2n x[n] (d) s[n] = x[n] * x[n]A N S :4(a) 2)5.0z(zz4)z(Y += |Z| > 0.5 (b) 2)2(16)(+=zzE (c)1||:)1(8)( 2 >+=