Given that z is a standard normal random variable, compute the following probabilities.P(-2.57 <  z < 0)Question 6Select one:a.0.4949b.0.5c.0.0051d.0.0501

To solve this problem, we need to use the standard normal distribution table or Z-table.

1. First, we need to find the probability that z is less than 0. This is P(z < 0). Since 0 is the mean of the standard normal distribution, P(z < 0) = 0.5.

2. Next, we need to find the probability that z is greater than -2.57. This is P(z > -2.57). Looking up -2.57 in the Z-table, we find that the corresponding probability is 0.0051.

3. To find the probability that -2.57 < z < 0, we subtract P(z > -2.57) from P(z < 0). So, P(-2.57 < z < 0) = P(z < 0) - P(z > -2.57) = 0.5 - 0.0051 = 0.4949.

So, the answer is a. 0.4949.