f a net force of 7 N was constantly applied on 400 g object at rest, how long will it take to raise itsvelocity to 80 m/s?2. A constant force acts on an object of mass 5 kg for a duration of 2 seconds; it increases the object'svelocity from 3 m/s to 7 m/s. Find the magnitude of the applied force. Now if the force was appliedfor a duration of 5 seconds, what would be the final velocity of the object?3. A car of mass 1500kg starting from rest can reach a speed of 20m/s within 10 seconds. What isthe accelerating force of the car engine?4. Derive Newton's first law of motion using second law of motion.5. What is the impulse given to an object if a force of 10000N acts on it for 0.1s?6. A force produces an acceleration of 5 m/s2 when applied to a body of mass 2 kg. What accelerationcan the same force produce when applied to a body of mass 8kg?7. For how long should a force of 100N act on a body of mass 20kg so that it acquires a velocity of100m/s
Question
f a net force of 7 N was constantly applied on 400 g object at rest, how long will it take to raise itsvelocity to 80 m/s?2. A constant force acts on an object of mass 5 kg for a duration of 2 seconds; it increases the object'svelocity from 3 m/s to 7 m/s. Find the magnitude of the applied force. Now if the force was appliedfor a duration of 5 seconds, what would be the final velocity of the object?3. A car of mass 1500kg starting from rest can reach a speed of 20m/s within 10 seconds. What isthe accelerating force of the car engine?4. Derive Newton's first law of motion using second law of motion.5. What is the impulse given to an object if a force of 10000N acts on it for 0.1s?6. A force produces an acceleration of 5 m/s2 when applied to a body of mass 2 kg. What accelerationcan the same force produce when applied to a body of mass 8kg?7. For how long should a force of 100N act on a body of mass 20kg so that it acquires a velocity of100m/s
Solution
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We can use the formula F = ma, where F is the force, m is the mass, and a is the acceleration. First, we need to convert the mass from grams to kilograms, so m = 400g = 0.4kg. The force F = 7N. So, the acceleration a = F/m = 7N/0.4kg = 17.5 m/s². Then, we use the formula v = at, where v is the final velocity, a is the acceleration, and t is the time. So, t = v/a = 80m/s / 17.5 m/s² = 4.57 seconds.
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The force can be calculated using the formula F = ma. The acceleration a can be calculated using the formula a = Δv/Δt, where Δv is the change in velocity and Δt is the change in time. So, a = (7m/s - 3m/s) / 2s = 2 m/s². Then, F = ma = 5kg * 2 m/s² = 10N. If the force is applied for 5 seconds, the final velocity v can be calculated using the formula v = u + at, where u is the initial velocity, a is the acceleration, and t is the time. So, v = 3m/s + 2 m
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