Assume that last year in a particular state with 700000 children there were 1214 children out of 30900 in a random sample who were diagnosed with Autism Spectrum Disorder. Nationally, 1 out of 88 children are diagnosed with ASD. Is there sufficient data to show that the incident rate of ASD is higher in that state than nationally? Test at the 2% level.P: PARAMETER     What is the correct parameter symbol for this problem?     Correct     What is the wording of the parameter in the context of this problem?     CorrectH: HYPOTHESES     Fill in the correct null and alternative hypotheses:     The value of p on this one is a fraction....leave it exact.     𝐻0: Correct Correct 188​Correct      𝐻𝐴: Correct Correct 188​Correct A: ASSUMPTIONS     Since Correct information was collected from each object, what conditions do we need to check?     Check all that apply.     𝑁≥20𝑛𝑛(1-𝑝̂)≥10σσ is known.σσ is unknown.𝑛≥30 or normal population.𝑛(1-𝑝)≥10𝑛𝑝≥10𝑛(𝑝̂)≥10Partially correct     Check those assumptions:     Round computations to 2 decimal places.          1. 𝑛𝑝 = 30900Incorrect which is Correct 10Correct          2. 𝑛(1-𝑝) = 30900Incorrect which is Correct 10Correct          3. 𝑁 = 1000000Incorrect which is Correct 30Incorrect              If no N is given in the problem, use 1000000N: NAME THE PROCEDURE     The conditions are met to use a .T: TEST STATISTIC     The symbol and value of the random variable on this problem are as follows:     Leave this answer as a fraction.     =      The formula set up of the test statistic is as follows.:       (Leave any values that were given as fractions as fractions) 𝑧=𝑝̂-𝑝𝑝(1-𝑝)𝑛=( - )/(( ⋅(1- )) / )       Final answer for the test statistic from technology.     Round to 2 decimal places:     z = O: OBTAIN THE P-VALUE     Report to 4 decimal places.     It is possible when rounded that a p-value is 0.0000     P-value = M: MAKE A DECISION     Since the p-value , we .S: STATE A CONCLUSION    There significant evidence to conclude

According to the February 2008 Federal Trade Commission report on consumer fraud and identity theft, 23% of all complaints in 2007 were for identity theft. In that year, assume some state had 422 complaints of identity theft out of 1550 consumer complaints. Do these data provide enough evidence to show that that state had a higher proportion of identity theft than 23%? Test at the 9% level.P: PARAMETER     What is the correct parameter symbol for this problem?          What is the wording of the parameter in the context of this problem?     H: HYPOTHESES     Fill in the correct null and alternative hypotheses:     𝐻0:      𝐻𝐴: A: ASSUMPTIONS     Since information was collected from each object, what conditions do we need to check?     Check all that apply.     𝑁≥20𝑛σσ is unknown.𝑛𝑝≥10𝑛(𝑝̂)≥10σσ is known.𝑛(1-𝑝)≥10𝑛(1-𝑝̂)≥10𝑛≥30 or normal population.     Check those assumptions:          1. 𝑛𝑝 = which is           2. 𝑛(1-𝑝) = which is           3. 𝑁 = which is               If no N is given in the problem, use 1000000N: NAME THE PROCEDURE     The conditions are met to use a .T: TEST STATISTIC     The symbol and value of the random variable on this problem are as follows:     Leave this answer as a fraction.     =      The formula set up of the test statistic is as follows.:       (Leave any values that were given as fractions as fractions) 𝑧=𝑝̂-𝑝𝑝(1-𝑝)𝑛=( - )/(( ⋅(1- )) / )       Final answer for the test statistic from technology.     Round to 2 decimal places:     z = O: OBTAIN THE P-VALUE     Report to 4 decimal places.     It is possible when rounded that a p-value is 0.0000     P-value = M: MAKE A DECISION     Since the p-value , we .S: STATE A CONCLUSION    There significant evidence to conclude

According to victimization surveys, the overall crime rate is __________ official reports indicate.A.ten times higher thanB.probably more than twice as high asC.the same asD.considerably lower than

In 2001, the polls found that 81% of American adults believed that there was a conspiracy in the death of President Kennedy. Assume a recent poll asked 1740 American adults if they believe there was a conspiracy in the assassination and it found that 1374 believe there was a conspiracy. Does the data show that the proportion of Americans who believe in this conspiracy is now lower? Test at the 5% level.P: PARAMETER     What is the correct parameter symbol for this problem?          What is the wording of the parameter in the context of this problem?     H: HYPOTHESES     Fill in the correct null and alternative hypotheses:     𝐻0:      𝐻𝐴: A: ASSUMPTIONS     Since information was collected from each object, what conditions do we need to check?     Check all that apply.     𝑛(𝑝̂)≥10𝑁≥20𝑛𝑛𝑝≥10𝑛(1-𝑝)≥10𝑛(1-𝑝̂)≥10σσ is known.𝑛≥30 or normal population.σσ is unknown.     Check those assumptions:          1. 𝑛𝑝 = which is           2. 𝑛(1-𝑝) = which is           3. 𝑁 = which is               If no N is given in the problem, use 1000000N: NAME THE PROCEDURE     The conditions are met to use a .T: TEST STATISTIC     The symbol and value of the random variable on this problem are as follows:     Leave this answer as a fraction.     =      The formula set up of the test statistic is as follows.:       (Leave any values that were given as fractions as fractions) 𝑧=𝑝̂-𝑝𝑝(1-𝑝)𝑛=( - )/(( ⋅(1- )) / )       Final answer for the test statistic from technology.     Round to 2 decimal places:     z = O: OBTAIN THE P-VALUE     Report to 4 decimal places.     It is possible when rounded that a p-value is 0.0000     P-value = M: MAKE A DECISION     Since the p-value , we .S: STATE A CONCLUSION    There significant evidence to conclude

In July of 2013, Australians were asked if they thought unemployment would increase, and 47% thought that it would increase. In November of 2013, they were asked again. At that time 570 out of 1300 said that they thought unemployment would increase. At the 8% level, is there enough evidence to show that the proportion of Australians in November 2013 who believe unemployment would increase is lower than the proportion who felt it would increase in July 2013?P: PARAMETER     What is the correct parameter symbol for this problem?     Correct     What is the wording of the parameter in the context of this problem?     CorrectH: HYPOTHESES     Fill in the correct null and alternative hypotheses:     𝐻0: Correct Correct .47Correct     𝐻𝐴: Correct Correct .47CorrectA: ASSUMPTIONS     Since Correct information was collected from each object, what conditions do we need to check?     Check all that apply.     𝑛≥30 or normal population.𝑛(𝑝̂)≥10𝑁≥20𝑛σσ is known.𝑛(1-𝑝̂)≥10𝑛𝑝≥10σσ is unknown.𝑛(1-𝑝)≥10Partially correct     Check those assumptions:          1. 𝑛𝑝 = 611Correct which is Correct 10Correct          2. 𝑛(1-𝑝) = 689Correct which is Correct 10Correct          3. 𝑁 = 1000000Correct which is Correct 1300Incorrect              If no N is given in the problem, use 1000000N: NAME THE PROCEDURE     The conditions are met to use a Correct .T: TEST STATISTIC     The symbol and value of the random variable on this problem are as follows:     Leave this answer as a fraction.     Incorrect = 5701300​Correct      The formula set up of the test statistic is as follows.:       (Leave any values that were given as fractions as fractions) 𝑧=𝑝̂-𝑝𝑝(1-𝑝)𝑛=( 5701300​Correct -.47Correct )/((.47Correct ⋅(1-.47Correct )) /1300Correct )       Final answer for the test statistic from technology.     Round to 2 decimal places:     z = −2.08IncorrectO: OBTAIN THE P-VALUE     Report to 4 decimal places.     It is possible when rounded that a p-value is 0.0000     P-value = .0148IncorrectM: MAKE A DECISION     Since the p-value .08Correct , we Correct .S: STATE A CONCLUSION    There Correct significant evidence to conclude Incorrect Correct

In July of 2013, Australians were asked if they thought unemployment would increase, and 47% thought that it would increase. In November of 2013, they were asked again. At that time 570 out of 1300 said that they thought unemployment would increase. At the 8% level, is there enough evidence to show that the proportion of Australians in November 2013 who believe unemployment would increase is lower than the proportion who felt it would increase in July 2013?P: PARAMETER     What is the correct parameter symbol for this problem?     Correct     What is the wording of the parameter in the context of this problem?     CorrectH: HYPOTHESES     Fill in the correct null and alternative hypotheses:     𝐻0: Correct Correct .47Correct     𝐻𝐴: Correct Correct .47CorrectA: ASSUMPTIONS     Since Correct information was collected from each object, what conditions do we need to check?     Check all that apply.     𝑛≥30 or normal population.𝑛(𝑝̂)≥10𝑁≥20𝑛σσ is known.𝑛(1-𝑝̂)≥10𝑛𝑝≥10σσ is unknown.𝑛(1-𝑝)≥10Partially correct     Check those assumptions:          1. 𝑛𝑝 = 611Correct which is Correct 10Correct          2. 𝑛(1-𝑝) = 689Correct which is Correct 10Correct          3. 𝑁 = 1000000Correct which is Correct $30$30​Incorrect              If no N is given in the problem, use 1000000N: NAME THE PROCEDURE     The conditions are met to use a Correct .T: TEST STATISTIC     The symbol and value of the random variable on this problem are as follows:     Leave this answer as a fraction.     Correct = 5701300​Correct      The formula set up of the test statistic is as follows.:       (Leave any values that were given as fractions as fractions) 𝑧=𝑝̂-𝑝𝑝(1-𝑝)𝑛=( 5701300​Correct -.47Correct )/((.47Correct ⋅(1-.47Correct )) /1300Correct )       Final answer for the test statistic from technology.     Round to 2 decimal places:     z = −2.08IncorrectO: OBTAIN THE P-VALUE     Report to 4 decimal places.     It is possible when rounded that a p-value is 0.0000     P-value = .0188IncorrectM: MAKE A DECISION     Since the p-value Correct .08Correct , we Correct .S: STATE A CONCLUSION    There Correct significant evidence to conclude Correct Incorrect