ASSIGNMENT 15 / 20Algebraic expressions (Part 2): ExponentsROOTS WITH MONOMIALSConsider the equation here, which has a missing quantity on the left side:144x□−−−−−√=12x2144𝑥◻=12𝑥2What number belongs in the □◻?Answer:□=◻= Are you sure? Take another look at your answer!Help! How should I type my answer?
Question
ASSIGNMENT 15 / 20Algebraic expressions (Part 2): ExponentsROOTS WITH MONOMIALSConsider the equation here, which has a missing quantity on the left side:144x□−−−−−√=12x2144𝑥◻=12𝑥2What number belongs in the □◻?Answer:□=◻= Are you sure? Take another look at your answer!Help! How should I type my answer?
Solution
The equation given is: √(144x^□) = 12x^2
We know that √144 = 12, so we can simplify the equation to: √(x^□) = x^2
The square root of a number is the same as raising that number to the power of 1/2. So, we can rewrite the equation as: x^(□/2) = x^2
In order for these two expressions to be equal, □/2 must be equal to 2. Solving for □ gives us □ = 2*2 = 4.
So, the number that belongs in the box is 4.
Similar Questions
ASSIGNMENT 4 / 20Algebraic expressions (Part 2): ExponentsDIVIDING POWERSSimplify the following expression:6m3n38m5n36𝑚3𝑛38𝑚5𝑛3INSTRUCTIONS:Use the ^ symbol to type an exponent if necessary. For example for m2𝑚2 type m𝑚^22.Use brackets to put multiple factors in the denominator. For example for 1mn1𝑚𝑛 type 1/(mn)1/(𝑚𝑛).Answer:Boo-yah! That's correct.Hence, evaluate 6m3n38m5n36𝑚3𝑛38𝑚5𝑛3 if m=2𝑚=2 and n=6𝑛=6.Answer: 2 attempts remaining
Algebraic expressions (Part 2): ExponentsALGEBRAIC FRACTIONSSimplify each of the following expressions:INSTRUCTION: Use the ^ symbol to type an exponent if necessary. For example for m2𝑚2 type m^2.Answer:1. 4m5×8m64m4=4𝑚5×8𝑚64𝑚4= 2. 4m5+8m64m4=4𝑚5+8𝑚64𝑚4=2 attempts remaining
Algebraic expressions (Part 2): ExponentsALGEBRAIC FRACTIONSSimplify each of the following expressions:INSTRUCTION: Use the ^ symbol to type an exponent if necessary. For example for g2𝑔2 type g^2.Answer:1. 6g4×4g22g=6𝑔4×4𝑔22𝑔= 2. 6g4+4g22g=6𝑔4+4𝑔22𝑔=2 attempts remaining
Algebraic expressions (Part 2): ExponentsDIVIDING POWERSThere is a missing number in the following equation. It is represented by the blue diamond, ⧫⧫. Determine the value of this missing number.(p2)2(p3)⧫=1p5(𝑝2)2(𝑝3)⧫=1𝑝5Answer:The value of the missing number is: .2 attempts remaining
Algebraic expressions (Part 2): ExponentsDIVIDING POWERSSimplify the following expression:−22j5k−12j2k2−22𝑗5𝑘−12𝑗2𝑘2INSTRUCTIONS:Use the ^ symbol to type an exponent if necessary. For example for j2𝑗2 type j𝑗^22.Use brackets to put multiple factors in the denominator. For example, to get 1jk1𝑗𝑘 you must type 1/(jk)1/(𝑗𝑘).Answer: 2 attempts remaining
Upgrade your grade with Knowee
Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.