If law of conservation of mass was to hold true, then 20.8 gm of BaCl2 on reaction with 9.8 gm of H2SO4 will produce 7.3 gm of HCl and BaSO4 equal to : 11.65 g 23 g 25.5 g 36 g
Question
If law of conservation of mass was to hold true, then 20.8 gm of BaCl2 on reaction with 9.8 gm of H2SO4 will produce 7.3 gm of HCl and BaSO4 equal to : 11.65 g 23 g 25.5 g 36 g
Solution
The law of conservation of mass states that the mass of the reactants in a chemical reaction must equal the mass of the products.
Given: Mass of BaCl2 = 20.8 gm Mass of H2SO4 = 9.8 gm Mass of HCl = 7.3 gm
We need to find the mass of BaSO4.
According to the law of conservation of mass: Mass of reactants = Mass of products
So, Mass of BaCl2 + Mass of H2SO4 = Mass of HCl + Mass of BaSO4
Substituting the given values: 20.8 gm + 9.8 gm = 7.3 gm + Mass of BaSO4
30.6 gm = 7.3 gm + Mass of BaSO4
Therefore, the Mass of BaSO4 = 30.6 gm - 7.3 gm = 23.3 gm
So, the closest answer is 23 g.
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