Pure oxygen boils at –183ºC and freezes at –219ºC. What state will the oxygen be in if the temperature is lowered to 50 K? Question 4 options: solid liquid gas plasma solution
Question
Pure oxygen boils at –183ºC and freezes at –219ºC. What state will the oxygen be in if the temperature is lowered to 50 K?
Question 4 options:
solid
liquid
gas
plasma
solution
Solution
The state of oxygen at 50 K would be solid.
Here's why:
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Convert the given temperatures from Celsius to Kelvin. The formula to convert Celsius to Kelvin is K = C + 273.15.
Boiling point of oxygen = -183ºC = -183 + 273.15 = 90.15 K Freezing point of oxygen = -219ºC = -219 + 273.15 = 54.15 K
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Compare the given temperature (50 K) with the boiling and freezing points.
The given temperature (50 K) is below the freezing point of oxygen (54.15 K), which means the oxygen would be in a solid state.
So, the correct option is "solid".
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