Maclaurin’s series expansion of e^x
Question
Maclaurin’s series expansion of e^x
Solution
To find the Maclaurin series expansion of e^x, we can use the formula:
e^x = 1 + x + (x^2)/2! + (x^3)/3! + (x^4)/4! + ...
Step 1: Write down the general form of the Maclaurin series expansion for e^x.
e^x = a0 + a1x + a2x^2 + a3x^3 + a4x^4 + ...
Step 2: Determine the coefficients a0, a1, a2, a3, a4, and so on.
To find the coefficients, we can use the formula:
an = f^n(0)/n!
where f^n(0) represents the nth derivative of e^x evaluated at x = 0.
Step 3: Calculate the derivatives of e^x.
The derivatives of e^x are:
f^0(x) = e^x f^1(x) = e^x f^2(x) = e^x f^3(x) = e^x f^4(x) = e^x ...
Step 4: Evaluate the derivatives at x = 0.
When x = 0, all the derivatives of e^x are equal to 1.
f^0(0) = 1 f^1(0) = 1 f^2(0) = 1 f^3(0) = 1 f^4(0) = 1 ...
Step 5: Substitute the values into the formula for the coefficients.
Using the formula an = f^n(0)/n!, we have:
a0 = f^0(0)/0! = 1/1 = 1 a1 = f^1(0)/1! = 1/1 = 1 a2 = f^2(0)/2! = 1/2 = 1/2 a3 = f^3(0)/3! = 1/6 = 1/6 a4 = f^4(0)/4! = 1/24 = 1/24 ...
Step 6: Write down the Maclaurin series expansion of e^x.
Using the coefficients we found, the Maclaurin series expansion of e^x is:
e^x = 1 + x + (x^2)/2! + (x^3)/3! + (x^4)/4! + ...
This expansion can be used to approximate the value of e^x for any value of x.
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