The sum of 4 integers in A.P is 24 their product 495 then C.D. isa.2b.4c.1d.3

The problem is asking for the common difference (C.D.) of an arithmetic progression (A.P.) of four integers whose sum is 24 and whose product is 495.

Let's denote the four numbers as a-d, a, a+d, a+2d.

Step 1: Sum of the numbers According to the problem, the sum of these four numbers is 24. So, we can write the equation as: (a-d) + a + (a+d) + (a+2d) = 24 Solving this equation, we get: 4a = 24 a = 6

Step 2: Product of the numbers The product of these four numbers is 495. So, we can write the equation as: (a-d) * a * (a+d) * (a+2d) = 495 Substituting a = 6, we get: (6-d) * 6 * (6+d) * (6+2d) = 495 Solving this equation, we get: d = 1

So, the common difference (C.D.) of the arithmetic progression (A.P.) is 1. Therefore, the answer is c.1.