so, what would the answer be for this question? :A golfer is trying to hit their ball over a 20 m tree. The ball leaves their club at an angle of 21° above the horizon. What is the minimum speed the golf ball would need to have after being hit by the club to make it over the tree, in m/s?
Question
so, what would the answer be for this question? :A golfer is trying to hit their ball over a 20 m tree. The ball leaves their club at an angle of 21° above the horizon. What is the minimum speed the golf ball would need to have after being hit by the club to make it over the tree, in m/s?
Solution
To solve this problem, we can use the physics formula for the maximum height of a projectile, which is given by:
h = (v^2 * sin^2(θ)) / (2 * g)
where:
- h is the height the ball needs to reach (20 m in this case),
- v is the speed of the ball,
- θ is the angle at which the ball is hit (21° in this case),
- g is the acceleration due to gravity (approximately 9.81 m/s^2 on Earth).
We need to solve this equation for v, the minimum speed the ball needs to have. Rearranging the equation gives us:
v = sqrt((2 * g * h) / sin^2(θ))
Substituting the given values into this equation:
v = sqrt((2 * 9.81 m/s^2 * 20 m) / sin^2(21°))
Calculating this gives us the minimum speed the ball needs to have in m/s.
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