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Find the linear approximation of the function g(x) = 51 + x at a = 0.

Question

Find the linear approximation of the function g(x) = 51 + x at a = 0.

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Solution

The linear approximation of a function at a certain point can be found using the formula for the equation of a tangent line, which is y = f(a) + f'(a)(x - a).

Here, we have the function g(x) = 51 + x and we want to find the linear approximation at a = 0.

Step 1: Find the value of the function at a, which is g(a). In this case, a = 0, so g(0) = 51 + 0 = 51.

Step 2: Find the derivative of the function, which is g'(x). The derivative of 51 + x is 1.

Step 3: Find the value of the derivative at a, which is g'(a). In this case, a = 0, so g'(0) = 1.

Step 4: Substitute these values into the formula for the equation of a tangent line. This gives us y = 51 + 1*(x - 0), which simplifies to y = 51 + x.

So, the linear approximation of the function g(x) = 51 + x at a = 0 is y = 51 + x.

This problem has been solved

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