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can you please give me practise problems for linear equation

Question

can you please give me practise problems for linear equation

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Solution

Sure, here are some practice problems for linear equations:

  1. Solve for x: 2x + 3 = 7
  2. Solve for y: 5y - 10 = 20
  3. Solve for z: 4z + 2 = 18
  4. Solve for x: 3x - 5 = 10
  5. Solve for y: 2y + 8 = 16
  6. Solve for x: 5x + 10 = 35
  7. Solve for y: 3y - 9 = 12
  8. Solve for x: 4x + 7 = 19
  9. Solve for y: 6y - 4 = 14
  10. Solve for x: 7x + 3 = 24

Remember, the goal is to isolate the variable on one side of the equation.

This problem has been solved

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Rinky planned to celebrate her mom’s birthday. She baked a cake and prepared lemonade.She bought few gulab jamoons and samosas as well. The number of gulab jamoons isdouble the number of samosas. Please help Rinky to form a linear equation in twovariable by taking number of gulab jamoon as X and the number of samosas as Y andanswer her questions given below.1. The linear equation that represents this situation isA) X+2Y=0 B) X-2Y=0C) 2X+Y=0 D) 2X-Y=02. She bought 8 jamoons, how many samosas did she buy?A) 2 B) 4C) 8 D) 163. If the total cost of jamoons and samosas is 100 rupees, and the cost of each jamoonis Rs. a and the cost of each samosa is Rs.b, then the equation representing thesituation isA) 8a+2b=100 B) 8a+8b=100C) 8a+16b=100 D) 8a+4b=1004. If the cost of one jamoon is Rs.5, then the cost of each samosa isA) Rs.30 B) Rs.7.50C) Rs.15 D) Rs.55. The graph of the equation of the above situation is a straight line that__________A) Is parallel to X- axis B) Is parallel to Y -axisC) Does not passes through the origin D) Passed through the origin

Solve the linear equation in three methods a)Substitution b) Elimination c) Graphical 1)      2x + 7 = 3y                                          2)   x – 3y = 5                                4x + 7y = 12                                                2x + 5y = -1                  3)    5x + 3y =4                                            4)   3x + 4y = 25       3x + 5y = 9                                                      x + y = 7

A rental car company charges $0.50 per mile and a flat rate of $30.00 for any type of sedan. If m represents the number of miles driven and C(m) represents the total cost for renting a sedan, what is the linear equation that represents a cost of $130?Responses130=30m+0.50130 is equal to 30m plus 0 point 50130=0.50m+30130 is equal to 0 point 50m plus 3030=130m+0.5030 is equal to 130m plus 0 point 5030=0.50m+130

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