find the value of z so that the specified area to the left of it would be 0.67

To find the value of z that leaves an area of 0.67 to the left of it, you would use the standard normal distribution table or a z-score calculator.

The standard normal distribution table lists z-scores and their corresponding percentiles. A percentile is the probability that a value on a distribution falls below a given score. In this case, we want to find the z-score for the 67th percentile (0.67).

1. Look for the closest value to 0.67 in the body of the standard normal distribution table. This value represents the area to the left of the z-score.

2. Once you find the closest value, look at the corresponding row and column headers to find the z-score.

If you are using a z-score calculator:

1. Input the area to the left (0.67) into the calculator.

2. The calculator will output the z-score.

Remember, the z-score represents how many standard deviations away a value is from the mean in a standard normal distribution.