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A 0.30-m radius automobile tire rotates how many rad after starting from rest and accelerating at a constant 3.0 rad/s2 over a 5.0-s interval?Select one:a.12 radb.37 radc.25 radd.0.50 rad

Question

A 0.30-m radius automobile tire rotates how many rad after starting from rest and accelerating at a constant 3.0 rad/s2 over a 5.0-s interval?Select one:a.12 radb.37 radc.25 radd.0.50 rad

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Solution

To solve this problem, we can use the formula for the distance traveled under constant acceleration, which is θ = ωit + 0.5α*t^2.

In this case, the initial angular velocity (ωi) is 0 (since the tire starts from rest), the angular acceleration (α) is 3.0 rad/s^2, and the time (t) is 5.0 s.

Substituting these values into the formula, we get:

θ = 05 + 0.535^2 = 0 + 0.53*25 = 0 + 37.5 = 37.5 rad

However, since the options are all integers, it seems like we should round to the nearest whole number, which would be 37 rad.

So, the answer is b. 37 rad.

This problem has been solved

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