A 0.30-m radius automobile tire rotates how many rad after starting from rest and accelerating at a constant 3.0 rad/s2 over a 5.0-s interval?Select one:a.12 radb.37 radc.25 radd.0.50 rad
Question
A 0.30-m radius automobile tire rotates how many rad after starting from rest and accelerating at a constant 3.0 rad/s2 over a 5.0-s interval?Select one:a.12 radb.37 radc.25 radd.0.50 rad
Solution
To solve this problem, we can use the formula for the distance traveled under constant acceleration, which is θ = ωit + 0.5α*t^2.
In this case, the initial angular velocity (ωi) is 0 (since the tire starts from rest), the angular acceleration (α) is 3.0 rad/s^2, and the time (t) is 5.0 s.
Substituting these values into the formula, we get:
θ = 05 + 0.535^2 = 0 + 0.53*25 = 0 + 37.5 = 37.5 rad
However, since the options are all integers, it seems like we should round to the nearest whole number, which would be 37 rad.
So, the answer is b. 37 rad.
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