If the Hartley oscillator is tuned at 1KHz with both inductor being equal valued having no mututal inductance, what is the value of op-amp feedback resistance if R1 = 10K Ohm?
Question
If the Hartley oscillator is tuned at 1KHz with both inductor being equal valued having no mututal inductance, what is the value of op-amp feedback resistance if R1 = 10K Ohm?
Solution 1
The Hartley oscillator is a type of LC oscillator where the frequency of oscillation is determined by the values of the inductors and capacitors in the circuit. The frequency of oscillation is given by the formula:
f = 1 / (2π√(LC))
where L is the inductance, C is the capacitance, and f is the frequency of oscillation.
Given that the frequency of oscillation is 1kHz and the inductors are equal in value, we can rearrange the formula to solve for the inductance:
L = 1 / (4π²f²C)
However, the problem does not provide a value for the capacitance, so we cannot calculate the inductance.
The op-amp feedback resistance in a Hartley oscillator is typically determined by the gain requirements of the circuit, not the frequency of oscillation. Therefore, without additional information, we cannot determine the value of the op-amp feedback resistance based on the given information.
If the op-amp is configured in a non-inverting amplifier configuration, the gain of the amplifier is given by the formula:
Gain = 1 + (Rf / R1)
where Rf is the feedback resistance and R1 is the resistance connected to the inverting input of the op-amp. However, without knowing the required gain of the circuit, we cannot solve for the feedback resistance.
Solution 2
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Solution 3
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