A person who has a certain amount with him goes to the market. He can buy 50 oranges or 40 mangoes with this amount. He retains 10% of the amount for taxi fare and buys 20 mangoes and of the balance he purchases oranges. The number of oranges he can purchase is?
Question
A person who has a certain amount with him goes to the market. He can buy 50 oranges or 40 mangoes with this amount. He retains 10% of the amount for taxi fare and buys 20 mangoes and of the balance he purchases oranges. The number of oranges he can purchase is?
Solution
Let's break down the problem step by step:
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Let's assume the total amount of money the person has is X.
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According to the problem, with this amount X, he can buy either 50 oranges or 40 mangoes. This means the cost of one orange is X/50 and the cost of one mango is X/40.
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The person retains 10% of the amount for taxi fare. So, he is left with 90% of X, which is 0.9X.
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He buys 20 mangoes. The cost of 20 mangoes is 20 * (X/40) = 0.5X.
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After buying the mangoes, he is left with 0.9X - 0.5X = 0.4X.
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With the remaining money, he buys oranges. The number of oranges he can buy is 0.4X / (X/50) = 20.
So, the person can buy 20 oranges.
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