Consider following reactions :-(a) N2(g) + O2(g) → 2NO(g); ΔH = X1(b) 2CO(g) + O2(g) → 2CO2(g); ΔH = X2(c) 2H2O(g) + O2(g) →2H2O2(g); ΔH = X3(d) PCl3(g) + Cl2(g) → PCl5(g); ΔH = X4In which case(s), ΔHƒ a, b, cdb, ca
Question
Consider following reactions :-(a) N2(g) + O2(g) → 2NO(g); ΔH = X1(b) 2CO(g) + O2(g) → 2CO2(g); ΔH = X2(c) 2H2O(g) + O2(g) →2H2O2(g); ΔH = X3(d) PCl3(g) + Cl2(g) → PCl5(g); ΔH = X4In which case(s), ΔHƒ a, b, cdb, ca
Solution
To determine in which case(s) the formation enthalpy (ΔHƒ) of a, b, c, and d is greater, we need to compare the values of X1, X2, X3, and X4.
(a) N2(g) + O2(g) → 2NO(g); ΔH = X1 (b) 2CO(g) + O2(g) → 2CO2(g); ΔH = X2 (c) 2H2O(g) + O2(g) → 2H2O2(g); ΔH = X3 (d) PCl3(g) + Cl2(g) → PCl5(g); ΔH = X4
To compare the values, we need to know the specific values of X1, X2, X3, and X4. Without this information, we cannot determine which case(s) have a greater formation enthalpy.
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