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0.200 mol of calcium fluoride, CaF2, is added to 50.0 cm3 of distilled water which is then made up to a total volume of 250 cm3. Determine the concentration of the solution, in mol dm–3.

Question

0.200 mol of calcium fluoride, CaF2, is added to 50.0 cm3 of distilled water which is then made up to a total volume of 250 cm3. Determine the concentration of the solution, in mol dm–3.

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Solution

To calculate the concentration of the solution, we need to use the formula for molarity which is:

Molarity (M) = moles of solute / volume of solution in liters

Given: Moles of solute (Calcium fluoride, CaF2) = 0.200 mol Volume of solution = 250 cm3

First, we need to convert the volume from cm3 to liters because the standard unit for volume in the formula is liters (1 dm3 = 1 liter and 1 liter = 1000 cm3).

So, 250 cm3 = 250 / 1000 = 0.25 liters

Now, we can substitute these values into the formula:

Molarity (M) = 0.200 mol / 0.25 liters = 0.8 mol dm–3

So, the concentration of the solution is 0.8 mol dm–3.

This problem has been solved

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