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6(m−2)+14=3(m+2)−10

Question

6(m−2)+14=3(m+2)−10

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Solution

Sure, let's solve the equation step by step:

  1. Distribute the numbers outside the parentheses on both sides of the equation:

    6m - 12 + 14 = 3m + 6 - 10

  2. Simplify both sides of the equation:

    6m + 2 = 3m - 4

  3. Subtract 3m from both sides to get all the m terms on one side:

    6m - 3m + 2 = -4

    This simplifies to:

    3m + 2 = -4

  4. Subtract 2 from both sides to isolate the m term:

    3m = -4 - 2

    This simplifies to:

    3m = -6

  5. Divide both sides by 3 to solve for m:

    m = -6 / 3

    This simplifies to:

    m = -2

So, the solution to the equation 6(m−2)+14=3(m+2)−10 is m = -2.

This problem has been solved

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