The potential of an electric dipole at a large but finite distance 'r' from the midpoint of a dipole is inversely proportional to r^2. So, the correct answer is b. "is inversely proportional to r^2".

Here's a step-by-step explanation:

1. The electric potential (V) due to a dipole at a point on the axial line is given by the formula V = kp cosθ / r^2, where k is Coulomb's constant, p is the dipole moment, θ is the angle between the dipole moment and the line joining the point to the dipole, and r is the distance from the point to the dipole.

2. At large distances (i.e., r size of the dipole), the dipole can be considered as a point dipole.

3. For a point dipole, the angle θ is always 180 degrees, so cosθ = -1.

4. Therefore, the potential V = -kp / r^2, which shows that the potential is inversely proportional to the square of the distance r.

So, the potential of an electric dipole at a large but finite distance 'r' from the midpoint of a dipole is inversely proportional to r^2.

Question

The potential of an electric dipole at a large but finite distance 'r' from the midpoint of a dipole is inversely proportional to r^2. So, the correct answer is b. "is inversely proportional to r^2".

Here's a step-by-step explanation:

1. The electric potential (V) due to a dipole at a point on the axial line is given by the formula V = kp cosθ / r^2, where k is Coulomb's constant, p is the dipole moment, θ is the angle between the dipole moment and the line joining the point to the dipole, and r is the distance from the point to the dipole.

2. At large distances (i.e., r >> size of the dipole), the dipole can be considered as a point dipole.

3. For a point dipole, the angle θ is always 180 degrees, so cosθ = -1.

4. Therefore, the potential V = -kp / r^2, which shows that the potential is inversely proportional to the square of the distance r.

So, the potential of an electric dipole at a large but finite distance 'r' from the midpoint of a dipole is inversely proportional to r^2.

Knowee AI · Accepted Answer

The potential of an electric dipole at a large but finite distance 'r' from the midpoint of a dipole is inversely proportional to r^2. So, the correct answer is b. "is inversely proportional to r^2".

Here's a step-by-step explanation:

1. The electric potential (V) due to a dipole at a point on the axial line is given by the formula V = kp cosθ / r^2, where k is Coulomb's constant, p is the dipole moment, θ is the angle between the dipole moment and the line joining the point to the dipole, and r is the distance from the point to the dipole.

2. At large distances (i.e., r >> size of the dipole), the dipole can be considered as a point dipole.

3. For a point dipole, the angle θ is always 180 degrees, so cosθ = -1.

4. Therefore, the potential V = -kp / r^2, which shows that the potential is inversely proportional to the square of the distance r.

So, the potential of an electric dipole at a large but finite distance 'r' from the midpoint of a dipole is inversely proportional to r^2.

The potential of an electric dipole at a large but finite distance 'r' from the mid point of a dipole Select one:a. is inversely proportional to r3b. is inversely proportional to r2c. Independent of rd. is inversely proportional to r

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