In a monohybrid experiment, the F1 hybrids (genotype Aa) are crossed. What is the probability that the offspring will be homozygous (AA or aa)?Multiple choice question.1/4 * 1/4 = 1/161/4 + 1/4 = 1/21/4 - 1/4 = 01/4 divided by 1/4 = 1
Question
In a monohybrid experiment, the F1 hybrids (genotype Aa) are crossed. What is the probability that the offspring will be homozygous (AA or aa)?Multiple choice question.1/4 * 1/4 = 1/161/4 + 1/4 = 1/21/4 - 1/4 = 01/4 divided by 1/4 = 1
Solution
The correct answer is 1/4 + 1/4 = 1/2.
Here's the step-by-step explanation:
In a monohybrid cross, the F1 hybrids (genotype Aa) are crossed. This means one parent has the genotype Aa and the other parent also has the genotype Aa.
The possible combinations of alleles that the offspring could inherit are: AA, Aa, aA, and aa.
The probability of getting AA is 1/4 (one out of four possible combinations). The same goes for aa.
So, the probability of the offspring being homozygous (either AA or aa) is the sum of these two probabilities, which is 1/4 (for AA) + 1/4 (for aa) = 1/2.
So, the correct answer to the multiple choice question is "1/4 + 1/4 = 1/2".
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