A particle is executing SHM on a straight line. A and B are two points at which its speed is zero. It passes through a certain point P (AP < BP) at successive interval of 0.5 sec and1.5 sec with a speed is 3 m/s, then:

Two particles are executing S.H.M in a straight line At t=0 one particle is at x1 = +A and the other at x2 = -A/2, and they are approaching towards each other. After what time they cross each other (A,T are same)

A particle moving in a straight line covers half the distance with speed of 3 m/s. The another half of the distance is covered in two equal time intervals with speed of 4.5 m/s and 7.5 m/s, respectively. The average speed of the particle during this motion is

A particle executing SHM has a period of 6 s. The time taken by the particle to move form mean position tohalf of the amplitude, starting from the mean position is

The motion of a particle along a straight line is described by equation :38 12x t t   where x is in metre and t in second. The retardation of the particlewhen its velocity becomes zero is

A particle moving along the straight line travels first 3m distance with speed 2 m/s, second 3m distance with speed 3 m/s and the third 3m distance with speed 6 m/s. The average speed of the particle is :-