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A person moves 30 𝑚 north and then20 𝑚 towards east and finally 30√2𝑚 insouth-west direction. The displacementof the person from the origin will be

Question

A person moves 30 𝑚 north and then20 𝑚 towards east and finally 30√2𝑚 insouth-west direction. The displacementof the person from the origin will be

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Solution

To find the displacement of the person from the origin, we need to calculate the resultant of the three movements.

Step 1: Draw a diagram First, let's draw a diagram to visualize the movements. The person moves 30m north, then 20m east, and finally 30√2m in the south-west direction.

Step 2: Break down the movements into components Next, we break down each movement into its x (east-west) and y (north-south) components.

  • The first movement is 30m north, which is 0m in the x direction and +30m in the y direction.
  • The second movement is 20m east, which is +20m in the x direction and 0m in the y direction.
  • The third movement is 30√2m in the south-west direction. This can be broken down into -30m in the x direction and -30m in the y direction (since south-west is a 45 degree angle, the x and y components are equal).

Step 3: Add up the components Now, we add up the x and y components separately:

  • Total x component = 0m (from the first movement) + 20m (from the second movement) - 30m (from the third movement) = -10m
  • Total y component = 30m (from the first movement) + 0m (from the second movement) - 30m (from the third movement) = 0m

Step 4: Calculate the displacement The displacement from the origin is the square root of the sum of the squares of the x and y components, which is √((-10m)^2 + (0m)^2) = 10m.

So, the displacement of the person from the origin is 10m.

This problem has been solved

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