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What will be the output of the following code?class Node:    def __init__(self, data=None):        self.data = data        self.next = Noneclass LinkedList:    def __init__(self):        self.head = None    def print_list(self):        current_node = self.head        while current_node:            print(current_node.data)            current_node = current_node.next    def insert_at_beginning(self, new_data):        new_node = Node(new_data)        new_node.next = self.head        self.head = new_nodellist = LinkedList()llist.insert_at_beginning(3)llist.insert_at_beginning(2)llist.insert_at_beginning(1)llist.print_list()Options1 2 31 3 22 3 13 2 1

Question

What will be the output of the following code?class Node:    def init(self, data=None):        self.data = data        self.next = Noneclass LinkedList:    def init(self):        self.head = None    def print_list(self):        current_node = self.head        while current_node:            print(current_node.data)            current_node = current_node.next    def insert_at_beginning(self, new_data):        new_node = Node(new_data)        new_node.next = self.head        self.head = new_nodellist = LinkedList()llist.insert_at_beginning(3)llist.insert_at_beginning(2)llist.insert_at_beginning(1)llist.print_list()Options1 2 31 3 22 3 13 2 1

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Solution

The output of the code will be:

1 2 3

So, the correct option is "1 2 3". This is because the insert_at_beginning method in the LinkedList class inserts new nodes at the beginning of the list. So, the last inserted node (which is 1) will be printed first, followed by 2 and then 3.

Similar Questions

What is the output of the following Python code snippet?class LinkedList:    def __init__(self):        self.head = None    def append(self, data):        new_node = Node(data)        if self.head is None:            self.head = new_node        else:            current = self.head            while current.next:                current = current.next            current.next = new_node    def display(self):        current = self.head        while current:            print(current.data, end=" ")            current = current.nextll = LinkedList()ll.append(1)ll.append(2)ll.display()

What does the following Python code snippet accomplish?class LinkedList:    def __init__(self):        self.head = None    def insert_at_beginning(self, data):        new_node = Node(data)        new_node.next = self.head        self.head = new_node

What does the following Python code snippet accomplish?class Node:    def __init__(self, data):        self.data = data        self.next = Nonenode1 = Node(1)node2 = Node(2)node1.next = node2Creates two linked list nodes with data 1 and 2, respectivelyCreates a singly linked list with two nodes containing data 1 and 2, respectivelyCreates a doubly linked list with two nodes containing data 1 and 2, respectivelyRaises a syntax error

What does the following Python code snippet accomplish?def reverse_linked_list(head):    prev = None    current = head    while current is not None:        next_node = current.next        current.next = prev        prev = current        current = next_node    head = prev    return head

what is the output of following python code? class myclass:    def __init__(self,a):        self.a = a        print(self.a)o=myclass()

1/2

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