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A wheel is rotating about an axis through its centre at 720 rpm. It is acted on by a constant torque opposing its motion for 8 second to bring it to rest finally. The value of torque in Nm is :– (given )

Question

A wheel is rotating about an axis through its centre at 720 rpm. It is acted on by a constant torque opposing its motion for 8 second to bring it to rest finally. The value of torque in Nm is :– (given )

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Solution

The problem seems to be incomplete as it does not provide the moment of inertia of the wheel which is required to calculate the torque. However, I can guide you through the steps to solve this problem if the moment of inertia was given.

  1. First, convert the rotational speed from revolutions per minute (rpm) to radians per second. We know that 1 revolution is equal to 2π radians and 1 minute is equal to 60 seconds. So, 720 rpm = 720 * 2π / 60 rad/s.

  2. The wheel comes to rest, so the final angular velocity is 0.

  3. Use the equation of motion in angular form: ωf = ωi + αt, where ωf is the final angular velocity, ωi is the initial angular velocity, α is the angular acceleration, and t is the time. Since the wheel comes to rest, ωf = 0. Solve for α.

  4. The torque τ is given by the equation τ = Iα, where I is the moment of inertia of the wheel. Solve for τ.

Remember, without the moment of inertia, we cannot calculate the torque.

This problem has been solved

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