Find the exact value of open vertical bar, minus, 5, minus, 4, i, close vertical bar∣−5−4i∣.
Question
Find the exact value of open vertical bar, minus, 5, minus, 4, i, close vertical bar∣−5−4i∣.
Solution
The given expression is the absolute value (or modulus) of a complex number. The complex number is -5 - 4i.
The formula to find the absolute value (or modulus) of a complex number a + bi is √(a² + b²).
Here, a = -5 and b = -4.
Step 1: Square a and b. a² = (-5)² = 25 b² = (-4)² = 16
Step 2: Add a² and b². a² + b² = 25 + 16 = 41
Step 3: Take the square root of the result. √(a² + b²) = √41
So, the exact value of ∣−5−4i∣ is √41.
Similar Questions
Find the exact value of open vertical bar, 5, plus, 8, i, close vertical bar∣5+8i∣.
Find the exact value of open vertical bar, 7, minus, 9, i, close vertical bar∣7−9i∣.
Solve for all values of bb in simplest form.open vertical bar, b, minus, 4, close vertical bar, equals, 38∣b−4∣=38
Find the value of [(4 – 5(4 – 5)4 ] 3
Evaluate (5−7i)4(5−7𝑖)4 and leave your answer in polar form with the angle in degrees and all numbers rounded to the nearest whole number.
Upgrade your grade with Knowee
Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.