Give the number of protons (p), neutrons (n), and electrons E) in one atom of 238U.146 p, 92 n, 92 e92 p, 92 n, 92 e92 p, 146 n, 92e146 p, 28 n, 146 e238 p, 146 n, 238 e

The correct answer is 92 protons (p), 146 neutrons (n), and 92 electrons (e).

Here's why:

The atomic number of an element, which is the number of protons in the nucleus of an atom, identifies the element. For Uranium (U), the atomic number is 92, so there are 92 protons.

The number of electrons in a neutral atom is equal to the number of protons, so there are also 92 electrons in a Uranium atom.

The atomic mass number (A) of an atom is the total number of protons and neutrons in its nucleus. The atomic mass number of Uranium-238 is 238. Since we know that there are 92 protons, we subtract 92 from 238 to find the number of neutrons. So, there are 146 neutrons in a Uranium-238 atom.