Calculate the solution to these simultaneous equations using the substitution method: (1)(1)𝑎a==𝑏+8b+8 (2)(2)𝑎+2𝑏a+2b==−7−7
Question
Calculate the solution to these simultaneous equations using the substitution method: (1)(1)𝑎a==𝑏+8b+8 (2)(2)𝑎+2𝑏a+2b==−7−7
Solution
Sure, let's solve these equations step by step:
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We have two equations here:
a = b + 8 ...(Equation 1)
a + 2b = -7 ...(Equation 2)
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From Equation 1, we can express 'a' in terms of 'b'. It's already done for us: a = b + 8.
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We substitute 'a' from Equation 1 into Equation 2:
(b + 8) + 2b = -7
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Simplify the equation:
3b + 8 = -7
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Solve for 'b':
3b = -7 - 8
3b = -15
b = -15 / 3
b = -5
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Substitute 'b' = -5 into Equation 1 to find 'a':
a = -5 + 8
a = 3
So, the solution to the system of equations is a = 3, b = -5.
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